At a glance
- 9631 Morrow Ave Ne, Albuquerque, NM 87112
About Jan Hollingsworth
Listed in the NPI registry as a mental health counselor, Jan K. Hollingsworth, LPCC practices in Albuquerque, NM. NPI 1740297100 identifies this record in the national registry.
Factual summary compiled by Guide.md from public records; not written by this provider.
Specialty
Credentials & Licensing
Contact Information
- (505) 275-2584
- Email not available
Practice Locations
9631 MORROW AVE NE
Albuquerque, NM 87112
Related providers
Connections drawn from the registry and from what providers have told us. A link here is not a referral or an endorsement.
Also at this address 1
Providers at the same street address. Each files their own registry entry, so a shared practice often appears under several different names.
Common questions
What does Jan K. Hollingsworth specialize in?
Jan K. Hollingsworth is a mental health counselor in Albuquerque, NM. That is the designation recorded for this NPI in the federal registry.
NPI registry
Where is Jan K. Hollingsworth located?
Jan K. Hollingsworth is listed at 9631 Morrow Ave Ne, Albuquerque, NM 87112. Addresses come from the NPI registry and can lag a move, so confirm before travelling.
NPI registry
What is Jan K. Hollingsworth's phone number?
The number on file is (505) 275-2584. Contact the office directly to confirm availability and scheduling.
NPI registry
What is Jan K. Hollingsworth's NPI number?
Jan K. Hollingsworth's National Provider Identifier is 1740297100. It is issued by the Centers for Medicare & Medicaid Services and is unique and permanent — it does not change if they move practice.
NPI registry
How long has Jan K. Hollingsworth been practicing?
Jan K. Hollingsworth has 20+ years experience. Registered with an NPI since 2006. National Provider Identifiers only began in 2005, so a provider who qualified earlier may have practiced for longer than this.
NPI registry
Has Jan K. Hollingsworth confirmed this information?
Not yet. This profile is built from public federal data and has not been confirmed by Jan K. Hollingsworth. If this is you, claiming it is free.
Guide.md
Guide.md listings do not constitute medical advice or an endorsement.